If 4tan θ 3 then cos2 θ – sin2 θ
WebIf 4tanθ=3, then ( 4sinθ−cosθ 4sinθ+cosθ) is equal to (A) 2 3 (B) 1 3 (C) 1 2 (D) 3 4 Solution The answer is (C). Given, 4tanθ= 3 ⇒ tanθ = 3 4 .......... (i) ∴ 4sinθ−cosθ 4sinθ+cosθ = 4sinθ cosθ−1 4sinθ cosθ+1 [divide by cosθ in both numerator and denominator] = 4tanθ−1 4tanθ+1 [∵ tanθ = sinθ cosθ] Web(3) (ii) Solve . 8 cot θ – 3 tan θ = 2, for 0 < θ < 90°, giving your answer to 1 decimal place. (5) (Total 12 marks) 17. (i) Given that cos(x + 30)° = 3 cos(x – 30)°, prove that tan x° = −. 2 3. (5) (ii) (a) Prove that . θ θ sin 2 1−cos2. ≡ tan θ . (3) (b) Verify that θ = 180° is a solution of the equation sin 2θ = 2 ...
If 4tan θ 3 then cos2 θ – sin2 θ
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Web18 okt. 2024 · If Sin A = 3/4, Calculate cos A and tan A. Solution: Given that, Sin A = 3/4 i.e. For a given problem, let Base = X Given: AB = Perpendicular = 3 , AC = Hypotenuse = 4 … WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Question: (1 point )cosθ=4/5 with 𝜃θ in Quadrant I. sin𝜙=5/13 with ϕ in Quadrant II. Find cos (𝜃−𝜙) sin (𝜃−𝜙) tan (𝜃−𝜙) (1 point )cosθ=4/5 with 𝜃θ in Quadrant I. sin𝜙=5/13 with ϕ in Quadrant II. Find
Web(3) (ii) Solve . 8 cot θ – 3 tan θ = 2, for 0 < θ < 90°, giving your answer to 1 decimal place. (5) (Total 12 marks) 17. (i) Given that cos(x + 30)° = 3 cos(x – 30)°, prove that tan x° = −. 2 … Webcos2 θ sinθ =− cos3 θ sin3 θ =−cot3 θ When θ=1 rad, d2y dx2 =−cot3 1=− 1 (tan1)3 =−0.2647, correct to 4 significant figures. Solved problems on differentiation of parametric equations Problem 5. The equation of the normal drawn to a curve at point (x1,y1) is given by: y −y1 =− 1 dy1 dx1 (x −x1) Determine the equation of ...
Web29 mrt. 2024 · If 4 tan θ = 3, then ( (4 sin θ - cos θ)/ (4 sin θ + cos θ)) is equal to (A) 2/3 (B) 1/3 (C) 1/2 (C) 3/4 This video is only available for Teachoo black users Subscribe … Web31 mrt. 2024 · If √3 tanθ = 3 sinθ, then the value of (sin 2 θ – cos 2 θ) is: 1 3 1/3 None of these Answer (Detailed Solution Below) Option 3 : 1/3 Crack CTET + State TET + PRT + …
Web29 mrt. 2024 · If 4 tan β = 3, then (4 sinβ - 3 cosβ)/ (4 sinβ + 3 cosβ ) = (a) 0 (b) 1/3 (c) 2/3 (d) 3/4 This question is inspired from Question 15 - NCERT Exemplar - MCQ - …
Web9 jan. 2024 · 4sin2 ϴ + 3sin2 ϴ+ 3cos2 ϴ = 4 4sin2 ϴ +3 (sin2 ϴ + cos2 ϴ) = 4 4sin2 ϴ + 3 = 4 4sin2 ϴ = 1 sin2 ϴ =1/4 sin ϴ = ½ sin ϴ =perp./hypo. = ½ So, perp. = 1k ; hypo. = 2k (Hypo)2 = (base)2 + (perp.)2 k2 = (base)2 + (2k)2 (base)2 = 4k2 – k2 base = root3 k tan ϴ = perp./base = k/root3 k so, tan ϴ =1/root3 Hope it helps !!!!!!!!!!!!!!!!!!!!!!!!! bb gun g15WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. davina blazerWeb12 mei 2024 · About this tutor ›. We are given tan (θ)=4/3, and we know tan is opposite over adjacent (o/a) so the triangle has two sides given. We need to first determine the last … bb gun firing rangeWeb4 jul. 2024 · Solution Given: 4 tan θ = 3 ⇒ tan θ = 3 4 Since, tan θ = P B ⇒ P = 3 and B = 4 Using Pythagoras theorem, P 2 + B 2 = H 2 ⇒ 3 2 + 4 2 = H 2 ⇒ H 2 = 9 + 16 ⇒ H 2 = 25 … davina bloomWebYour assumption is correct. Then (sin(2θ))2 = (2sin(θ)cos(θ))2 = 4sin2 θcos2 θ. More Items Examples Quadratic equation x2 − 4x − 5 = 0 Trigonometry 4sinθ cosθ = 2sinθ Linear … bb gun funnyWebGiven: 4 tan θ = 3 ⇒ tan θ = 3/4. Let us suppose a right angle triangle ABC right angled at B, with one of the acute angle θ. Let the sides be BC = 3kand AB = 4k, where k is a positive … davina blakeWebIf 4 tan theta = 3 , then evaluate (4sintheta-costheta) (4sintheta+costheta) Question If 4tanθ=3, then evaluate (4sinθ+cosθ)(4sinθ−cosθ) Easy Solution Verified by Toppr Given … bb gun g18